Teacher Jerks off a Student's Dick in University Classroom
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Teacher jerks off a student's cock in classroom during university class and risks getting caught He touches her hot pussy to orgasm - MissCreamy
Published by Miss_Creamy
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U of x = 1 + ex.
U of x, that's it.
As soon as I get U, what do I calculate?
Now, I said earlier, the derivative of a sum of function is the sum of derivatives.
When I want to drift 1 + ex, how do I do it?
I'm doing U's of x = 1,0, ex.
It doesn't change.
It's ex, is it good?
The derivative of 1 is 0, the derivative of X, it's ex.
Now, are you okay with me spelling that way?
F is U2 form.
And F is U2.
What's the derivative gonna be?
Which means your difficulty in doing the opposite, which is what you're doing, it's not difficult.
You say, am I looking for a primitive or am I looking for a derivative?
That's 2U, I multiply by U.
All I'm saying is, when I'm drifting, U2, I'm doing what I'm doing for ex-per-2, when I'm drifting, I'm doing 2x2.
So now I'm 2U, but I'm multiplying by U.
That's the idea.
When you drift off, you go 4x2.
When you're drifting U4, you'll be 4U3, but once U.
You see, One, when you drift Xn, it's nxn-1.
One, it's N-1U.
So the U2 derivative, what's it gonna be?
2U.
So expa2x = 2U'.
Are you all right?
Try this one on me.
F2x = In.
F2x = In.
So here, in the same way, we're gonna pose Po = In.
We're gonna do it automatically.
As soon as you've landed U, you calculate U's.
So U's = 1/x.
Are you all right?
So I'm rewriting f.
Do you agree that F is U2 form?
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